"use strict"; exports.intlFormatDistance = intlFormatDistance; var _index = require("./constants.js"); var _index2 = require("./differenceInCalendarDays.js"); var _index3 = require("./differenceInCalendarMonths.js"); var _index4 = require("./differenceInCalendarQuarters.js"); var _index5 = require("./differenceInCalendarWeeks.js"); var _index6 = require("./differenceInCalendarYears.js"); var _index7 = require("./differenceInHours.js"); var _index8 = require("./differenceInMinutes.js"); var _index9 = require("./differenceInSeconds.js"); var _index10 = require("./toDate.js"); /** * The {@link intlFormatDistance} function options. */ /** * The unit used to format the distance in {@link intlFormatDistance}. */ /** * @name intlFormatDistance * @category Common Helpers * @summary Formats distance between two dates in a human-readable format * @description * The function calculates the difference between two dates and formats it as a human-readable string. * * The function will pick the most appropriate unit depending on the distance between dates. For example, if the distance is a few hours, it might return `x hours`. If the distance is a few months, it might return `x months`. * * You can also specify a unit to force using it regardless of the distance to get a result like `123456 hours`. * * See the table below for the unit picking logic: * * | Distance between dates | Result (past) | Result (future) | * | ---------------------- | -------------- | --------------- | * | 0 seconds | now | now | * | 1-59 seconds | X seconds ago | in X seconds | * | 1-59 minutes | X minutes ago | in X minutes | * | 1-23 hours | X hours ago | in X hours | * | 1 day | yesterday | tomorrow | * | 2-6 days | X days ago | in X days | * | 7 days | last week | next week | * | 8 days-1 month | X weeks ago | in X weeks | * | 1 month | last month | next month | * | 2-3 months | X months ago | in X months | * | 1 quarter | last quarter | next quarter | * | 2-3 quarters | X quarters ago | in X quarters | * | 1 year | last year | next year | * | 2+ years | X years ago | in X years | * * @typeParam DateType - The `Date` type, the function operates on. Gets inferred from passed arguments. Allows to use extensions like [`UTCDate`](https://github.com/date-fns/utc). * * @param date - The date * @param baseDate - The date to compare with. * @param options - An object with options. * See MDN for details [Locale identification and negotiation](https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Intl#locale_identification_and_negotiation) * The narrow one could be similar to the short one for some locales. * * @returns The distance in words according to language-sensitive relative time formatting. * * @throws `date` must not be Invalid Date * @throws `baseDate` must not be Invalid Date * @throws `options.unit` must not be invalid Unit * @throws `options.locale` must not be invalid locale * @throws `options.localeMatcher` must not be invalid localeMatcher * @throws `options.numeric` must not be invalid numeric * @throws `options.style` must not be invalid style * * @example * // What is the distance between the dates when the fist date is after the second? * intlFormatDistance( * new Date(1986, 3, 4, 11, 30, 0), * new Date(1986, 3, 4, 10, 30, 0) * ) * //=> 'in 1 hour' * * // What is the distance between the dates when the fist date is before the second? * intlFormatDistance( * new Date(1986, 3, 4, 10, 30, 0), * new Date(1986, 3, 4, 11, 30, 0) * ) * //=> '1 hour ago' * * @example * // Use the unit option to force the function to output the result in quarters. Without setting it, the example would return "next year" * intlFormatDistance( * new Date(1987, 6, 4, 10, 30, 0), * new Date(1986, 3, 4, 10, 30, 0), * { unit: 'quarter' } * ) * //=> 'in 5 quarters' * * @example * // Use the locale option to get the result in Spanish. Without setting it, the example would return "in 1 hour". * intlFormatDistance( * new Date(1986, 3, 4, 11, 30, 0), * new Date(1986, 3, 4, 10, 30, 0), * { locale: 'es' } * ) * //=> 'dentro de 1 hora' * * @example * // Use the numeric option to force the function to use numeric values. Without setting it, the example would return "tomorrow". * intlFormatDistance( * new Date(1986, 3, 5, 11, 30, 0), * new Date(1986, 3, 4, 11, 30, 0), * { numeric: 'always' } * ) * //=> 'in 1 day' * * @example * // Use the style option to force the function to use short values. Without setting it, the example would return "in 2 years". * intlFormatDistance( * new Date(1988, 3, 4, 11, 30, 0), * new Date(1986, 3, 4, 11, 30, 0), * { style: 'short' } * ) * //=> 'in 2 yr' */ function intlFormatDistance(date, baseDate, options) { let value = 0; let unit; const dateLeft = (0, _index10.toDate)(date); const dateRight = (0, _index10.toDate)(baseDate); if (!options?.unit) { // Get the unit based on diffInSeconds calculations if no unit is specified const diffInSeconds = (0, _index9.differenceInSeconds)(dateLeft, dateRight); // The smallest unit if (Math.abs(diffInSeconds) < _index.secondsInMinute) { value = (0, _index9.differenceInSeconds)(dateLeft, dateRight); unit = "second"; } else if (Math.abs(diffInSeconds) < _index.secondsInHour) { value = (0, _index8.differenceInMinutes)(dateLeft, dateRight); unit = "minute"; } else if ( Math.abs(diffInSeconds) < _index.secondsInDay && Math.abs((0, _index2.differenceInCalendarDays)(dateLeft, dateRight)) < 1 ) { value = (0, _index7.differenceInHours)(dateLeft, dateRight); unit = "hour"; } else if ( Math.abs(diffInSeconds) < _index.secondsInWeek && (value = (0, _index2.differenceInCalendarDays)(dateLeft, dateRight)) && Math.abs(value) < 7 ) { unit = "day"; } else if (Math.abs(diffInSeconds) < _index.secondsInMonth) { value = (0, _index5.differenceInCalendarWeeks)(dateLeft, dateRight); unit = "week"; } else if (Math.abs(diffInSeconds) < _index.secondsInQuarter) { value = (0, _index3.differenceInCalendarMonths)(dateLeft, dateRight); unit = "month"; } else if (Math.abs(diffInSeconds) < _index.secondsInYear) { if ((0, _index4.differenceInCalendarQuarters)(dateLeft, dateRight) < 4) { // To filter out cases that are less than a year but match 4 quarters value = (0, _index4.differenceInCalendarQuarters)(dateLeft, dateRight); unit = "quarter"; } else { value = (0, _index6.differenceInCalendarYears)(dateLeft, dateRight); unit = "year"; } } else { value = (0, _index6.differenceInCalendarYears)(dateLeft, dateRight); unit = "year"; } } else { // Get the value if unit is specified unit = options?.unit; if (unit === "second") { value = (0, _index9.differenceInSeconds)(dateLeft, dateRight); } else if (unit === "minute") { value = (0, _index8.differenceInMinutes)(dateLeft, dateRight); } else if (unit === "hour") { value = (0, _index7.differenceInHours)(dateLeft, dateRight); } else if (unit === "day") { value = (0, _index2.differenceInCalendarDays)(dateLeft, dateRight); } else if (unit === "week") { value = (0, _index5.differenceInCalendarWeeks)(dateLeft, dateRight); } else if (unit === "month") { value = (0, _index3.differenceInCalendarMonths)(dateLeft, dateRight); } else if (unit === "quarter") { value = (0, _index4.differenceInCalendarQuarters)(dateLeft, dateRight); } else if (unit === "year") { value = (0, _index6.differenceInCalendarYears)(dateLeft, dateRight); } } const rtf = new Intl.RelativeTimeFormat(options?.locale, { localeMatcher: options?.localeMatcher, numeric: options?.numeric || "auto", style: options?.style, }); return rtf.format(value, unit); }