42 lines
1.5 KiB
Markdown
42 lines
1.5 KiB
Markdown
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# Is Module
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Check whether a source string looks like an ES6 module.
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This doesn't actually execute the code,
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and doesn't check other module types.
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So source strings without any module loaders returns `false`.
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This is just what I need from https://github.com/yahoo/js-module-formats, which actually executes the sauce string in a subcontext.
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## API
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```js
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var isES6Module = require('is-module');
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console.log(isES6Module('import * from "emitter";')) // => true
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```
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## License
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(The MIT License)
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Copyright (c) 2014 segmentio <team@segment.io>
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Permission is hereby granted, free of charge, to any person obtaining
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a copy of this software and associated documentation files (the
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'Software'), to deal in the Software without restriction, including
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without limitation the rights to use, copy, modify, merge, publish,
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distribute, sublicense, and/or sell copies of the Software, and to
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permit persons to whom the Software is furnished to do so, subject to
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the following conditions:
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The above copyright notice and this permission notice shall be
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included in all copies or substantial portions of the Software.
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THE SOFTWARE IS PROVIDED 'AS IS', WITHOUT WARRANTY OF ANY KIND,
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EXPRESS OR IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF
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MERCHANTABILITY, FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT.
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IN NO EVENT SHALL THE AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY
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CLAIM, DAMAGES OR OTHER LIABILITY, WHETHER IN AN ACTION OF CONTRACT,
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TORT OR OTHERWISE, ARISING FROM, OUT OF OR IN CONNECTION WITH THE
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SOFTWARE OR THE USE OR OTHER DEALINGS IN THE SOFTWARE.
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